Problem
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as
1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is
2
.
Note: m and n will be at most 100.
Analysis
- Similar to Unique Path except that we need to decide whether a position has obstacle or not
- If yes, the number of ways to it is 0
Code
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public class Solution { | |
public int uniquePathsWithObstacles(int[][] grid) { | |
int m = grid.length; | |
int n = grid[0].length; | |
int[] count = new int[n]; | |
for(int i=0; i<m; i++){ | |
for(int j=0; j<n; j++){ | |
//Case 1: has obstacle, then set as zero | |
if(grid[i][j]==1) count[j] = 0; | |
//Deal with i==0, j==0 | |
else if(i==0 && j==0) count[j] = 1; | |
else if(j==0) count[j] = count[j]; | |
else count[j] = count[j] + count[j-1]; | |
} | |
} | |
return count[n-1]; | |
} | |
} |
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